load CatalogItem array in treeview

Hi,

i would like to load my array 'items' in a treeview

CatalogItem[] items = rs.ListChildren("/", true);

is there anyway that automatically does the layout or do i have to check what the type is of everey object so I can indent correctly.

thanks
I'm really looking for this one :).

I'm trying to do it manually but I can't find a way to get the reports in the right structure. I'll show what I want to accomplish and how I am trying it now:

WANTED LIST:
+ Adventureworks
- Company Sales
- Employee Sales Summary
+ Subfolder
- Report from subfolder
- Report from subfolder

Code trying to get there (not thinking of subfolders yet):

rs.Credentials = System.Net.CredentialCache.DefaultCredentials;
CatalogItem[] items = rs.ListChildren("/", false);
foreach (CatalogItem ci in items)
{
cmbRapporten.Nodes.Add(ci.Name);
CatalogItem[] test = rs.ListChildren("/" + ci.Name.ToString(), false);
foreach(CatalogItem ti in test)
{
cmbRapporten.Nodes.Add(ti.Name);
}
}
EXPLANATION

I ask for the root folder's children (not recursive) and then list them in my treeview cmbRapporten then I create a new CatalogItem[] = test, where I list the children of the current folder in the CatalogItem[] items. Everything appears fine but it's all in one line down. How do I couple them with their parents folder.

greetings
|||Hi,

so I got there to fill the treeview not looking at subfolders with this code (pretty simple if you ask me ;))

[CODE]
ReportingService2005 rs = new ReportingService2005();
rs.Credentials = System.Net.CredentialCache.DefaultCredentials;
CatalogItem[] items = rs.ListChildren("/", false);
foreach (CatalogItem item in items)
{
cmbRapporten.Nodes.Add(item.Name);
if (item.Type.ToString() == "Folder")
{
CatalogItem[] childs = rs.ListChildren("/" + item.Name.ToString(), false);
foreach (CatalogItem child in childs)
{
cmbRapporten.Nodes[counter].Nodes.Add(child.Name);
}
counter++;
}
}
[/CODE]

Gives me a nice treeview in the designer but I'm still not content ;).

If one of the items in the object childs is a folder then there should be added another subnode. I'll visualize it for better understanding:

Now i support:

+ FOLDER
-REPORT
-REPORT
-SUBFOLDER
-REPORT

But I want the subfolder to display it's items too. So I will have to make a generic method and then call it with two parameters i thought. The string path wich is the path on the report server that should List it's children. Second of al I have to pass the Node number. But sometimes I will have to pass one node number while other times I will have to pass multiple node numbers... I have no idea to make such an method. Could somebody help with this.

Do I make sense or should I rephrase everything.

Greetings

ListChildren Error

If I call the ListChildren() in ReportingService2005, and the network is
connected, it works great.
If I call the ListChildren() in ReportingService2005, and the network is not
connected, I get a really ugly exception.
I'd like to find an API in ReportingService2005 to detect if reporting
services is running and accessible on the SQL server before calling
ListChildren from the client. Any suggestions on what to call before calling
ListChildren?
Thanks
--
RandyHi Randy,
Thank you for posting.
As for the ListChildren method, it is one of the webservice function of the
ReportingService2005 service class, and so far there is no built-in
methods for check the service connection status or availability.
#ReportingService2005 Methods
http://msdn2.microsoft.com/en-us/library/microsoft.wssux.reportingserviceswe
bservice.rsmanagementservice2005.reportingservice2005_methods(SQL.90).aspx
Actually, since webservice method call is tranferred over underlying
transport protocol(normally it is http), so this should be done by our own
application's code to check the protocol connection wellness. For example,
in our application which call the webservice methods, we can use exception
block (try...catch...) to capture any exception when perform webservice
call to the SSRS service, if any underlying exception occurs( like http 500
service unavailable error), we can get that the service is currently not
available.
Regards,
Steven Cheng
Microsoft Online Community Support
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